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A rectangle has a length that is 6 more than 4

times the width. The perimeter is 41
What is the width of the rectangle?
round to 2 decimals (hundredth)
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User Kurt Huwig
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1 Answer

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Final answer:

The width of the rectangle is approximately 2.9


Step-by-step explanation:

To find the width of the rectangle, we need to set up an equation based on the given information. Let's assume the width of the rectangle is 'w'. According to the problem, the length of the rectangle is 6 more than 4 times the width, which can be expressed as '4w + 6'.

The perimeter of a rectangle is given by the formula: 2(length + width). So, for this rectangle, the perimeter is 2(4w + 6 + w), which is equal to 41. Simplifying this equation, 2(5w + 6) = 41.

We can solve this equation to find the value of 'w'. After simplifying, we get 10w + 12 = 41. By subtracting 12 from both sides, we get 10w = 29. Finally, dividing both sides by 10, we find that the width of the rectangle is approximately 2.9 (rounded to two decimal places).


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User DexJ
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