Question

14) The angle of elevationfrom a point 116 meters fromthe base of the Eiffel Towerto the top of the tower is68.9°. Find the approximateheight of the tower to thenearest meter.

Answer 1

Given data:

The given angle of elevation is θ= 68.9°.

The horizontal distance is d=116 m.

The expression for tanθ is,

`\begin{gathered} \tan \theta=(h)/(d) \\ \tan (68.9^(\circ))=\frac{h}{116\text{ m}} \\ h=300.62\text{ m} \\ \approx301\text{ m} \end{gathered}`

Thus, the height of the tower is 301 m.