Question

two years later a father will be 8 years more than 3 times the age of the son. taking the present age of father and son as x and y respectively. write a linear equation

Answer 1

x = 3y + 12

Explanation:

Let's use "x" to represent the present age of the father and "y" to represent the present age of the son. We are given that two years later, the father's age will be 8 years more than 3 times the age of the son. This can be expressed as:

(x + 2) = 3(y + 2) + 8

Now, simplify this equation:

x + 2 = 3y + 6 + 8

x + 2 = 3y + 14

Now, subtract 2 from both sides to isolate "x":

x = 3y + 14 - 2

x = 3y + 12

So, the linear equation that represents the relationship between the present age of the father (x) and the present age of the son (y) is:

x = 3y + 12