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if the length of certain rectangle is decreased by 4 cm and breadth is increased by 2 cm, it would result in a square of the same area. what is the perimeter of the original rectangle?

User Danieltmbr
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Answer:

To find the perimeter of the original rectangle, we first need to find the dimensions of the rectangle.

Let's assume the length of the original rectangle is L cm and the breadth is B cm.

According to the given information, if the length is decreased by 4 cm, the new length becomes (L - 4) cm. Similarly, if the breadth is increased by 2 cm, the new breadth becomes (B + 2) cm.

We are told that this new rectangle with dimensions (L - 4) cm and (B + 2) cm is actually a square with the same area as the original rectangle.

The area of a rectangle is given by length multiplied by breadth. So, the area of the original rectangle is L * B square cm.

The area of the new square is equal to the area of the original rectangle. Therefore, we can set up the equation:

(L - 4) * (B + 2) = L * B

Expanding the equation:

LB - 4B + 2L - 8 = LB

Simplifying the equation:

2L - 4B - 8 = 0

2L = 4B + 8

L = 2B + 4

Now that we have an equation relating the length and breadth of the original rectangle, we can find the perimeter.

The perimeter of a rectangle is given by the formula: 2 * (length + breadth).

Substituting the value of L from the equation above, we get:

Perimeter = 2 * [(2B + 4) + B]

Perimeter = 2 * (3B + 4)

Perimeter = 6B + 8

Therefore, the perimeter of the original rectangle is 6B + 8 cm.

Explanation:

User Terminality
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