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Suppose r varies directly as the square of m, and inversely as s. If r=15 when m=9 and s=9 , find r when m=45 and s=9.

User Dynamitem
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1 Answer

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To solve this problem, we can use the method of direct variation, which states that two quantities that are directly proportional can be represented by the equation y = kx, where k is the proportionality constant.

From the problem, we know that r varies directly as m² and inversely as s. So, we can represent this as the equation r = k * m² / s, where k is our proportionality constant.

Step 1: Find the constant of variation, k

We first use the initial values we know (r_initial = 15, m_initial = 9, s_initial = 9) to determine the constant k. We plug these values into our equation which gives us:

k = r_initial * s_initial / m_initial²

k = 15 * 9 / 9²

k = 1.6666666666666667

This is our constant of proportionality.

Step 2: Find the final value of r (r_final)

Now we know the value of k, we can use this alongside other given values (m_final = 45, s_final = 9) to find our final value for r.

Plugging the values into the equation r = k * m² / s, we get:

r_final = k * m_final² / s_final

r_final = 1.6666666666666667 * 45² / 9

r_final = 375

So when m is 45 and s is 9, r is 375.

User Zimbabao
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