Question

What's y+1=1/9(x+2) in slope intercept form? thanks :D

Answer 1

Answer: y = 1/9x - 7/9

Explanation:

To convert the equation y+1=1/9(x+2) into slope-intercept form y=mx+b, where m is the slope and b is the y-intercept, you can follow these steps:

1. First, distribute 1/9 to both terms in the parentheses on the right side of the equation:

y + 1 = 1/9x + 2/9

2. Next, isolate y by subtracting 1 from both sides of the equation:

y = 1/9x + 2/9 - 1

3. Simplify the constants on the right side:

y = 1/9x - 7/9

So, the equation in slope-intercept form is y = 1/9x - 7/9.

Answer 2

`y = (1)/(9)x -(7)/(9)`

Explanation:

Given equation:

`y + 1 = (1)/(9)(x + 2)`

To write the given equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, begin by distributing 1/9 on the right side of the equation:

`y + 1 = (1)/(9)x + (2)/(9)`

Now, isolate y on the left side by subtracting 1 from both sides:

`y = (1)/(9)x + (2)/(9) - 1`

Simplify the right side:

`y = (1)/(9)x + (2)/(9) - (9)/(9)`

`y = (1)/(9)x + (2-9)/(9)`

`y = (1)/(9)x + (-7)/(9)`

`y = (1)/(9)x -(7)/(9)`

Therefore, the given equation in slope-intercept form is:

`\large\boxed{\boxed{y = (1)/(9)x -(7)/(9)}}`