Answer:
x = 277.5 g CaCO3
Step-by-step explanation:
The question is asking about the formation of calcium carbonate (CaCO3) from a reaction with water. The reaction is as follows:
Calcium cyanamide reacts with water to form calcium carbonate and ammonia via the following reaction:
CaCN2 (s) + 3H2O (l) → CaCO3 (s) + 2NH3 (g)
To solve this problem, we need to use stoichiometry, which is a method in chemistry for calculating amounts in reactions.
According to a source, 157 grams of water react with Calcium cyanamide to produce approximately 290.74 grams of CaCO3.
So, if we want to find out how many grams of CaCO3 form when 150 g of water react, we can set up a proportion:
157 g H2O : 290.74 g CaCO3 = 150 g H2O : x g CaCO3
Solving for x gives us the amount of CaCO3 produced when 150 g of water react.
Here's the calculation:
x = (290.74 g CaCO3 / 157 g H2O) * 150 g H2O
This will give us the amount of CaCO3 produced in grams.
x = (290.74 g CaCO3 / 157 g H2O) * 150 g H2O
This simplifies to:
x = 277.5 g CaCO3
So, if 150 g of water react, approximately 277.5 g of CaCO3 will form.
Hope this helps! :)