121k views
0 votes
Combining 0.288 mol Fe2O3 with excess carbon produced 18.1 g Fe. What is the actual yield of iron in moles

User KFichter
by
7.7k points

1 Answer

5 votes

Answer:

To calculate the actual yield of iron in moles, we need to use the molar mass of iron (Fe) and the given mass of iron produced.

The molar mass of iron (Fe) is approximately 55.845 g/mol.

Given:

Amount of Fe2O3 = 0.288 mol

Mass of Fe produced = 18.1 g

To find the moles of Fe produced, we can use the molar mass of Fe:

moles of Fe = mass of Fe / molar mass of Fe

moles of Fe = 18.1 g / 55.845 g/mol

moles of Fe ≈ 0.324 mol

Therefore, the actual yield of iron in moles is approximately 0.324 mol.

User DrKaoliN
by
7.5k points