This problem can be solved by using the formula for the forces exerted on a charged particle by an electric field, F=qE, and by a magnetic field, F=qvB, and then determining the net force on the proton.
Given parameters:
- The electric field (E) is 300 V/m.
- The magnetic field (B) is 0.65 T.
- The velocity of the proton (v) is 0 m/s, because it's moving at a constant velocity.
- The charge of a proton (q) is 1.6 x 10^-19 C.
Step 1:
Calculate the force exerted by the electric field using the formula F=qE:
This gives us F = (1.6 x 10^-19 C) * (300 V/m) = 4.8 x 10^-17 N.
Step 2:
Calculate the force exerted by the magnetic field using the formula F=qvB:
Since the proton's velocity is 0 m/s, the force due to the magnetic field will be zero.
Step 3:
Because the proton is moving at a constant velocity, the net force on the proton must be zero. According to Newton's First Law of Motion, no force is needed in the direction of motion when an object is moving at a constant speed. Therefore, the forces due to the electric field and magnetic field must balance each other.
So, the magnitude of the net force on the proton is 0 N. To summarize:
- The force due to the electric field is 4.8 x 10^-17 N.
- The force due to the magnetic field is 0 N.
- The net force on the proton is 0 N.