Question

Water boils at different temperatures at different elevations. The boiling temperature of water is 212°F at sea level (0 feet) but drops about 1.72° F for every 1,000 feet of elevation. Write a formula for the boiling point at a given elevation. Then solve the formula for the elevation when the boiling point for water is 190°F. Determine a formula for the boiling point b, in degrees Fahrenheit, at elevation h, in feet. (Type an equation. Simplify your answer. Do not include the degree symbol in your answer.)

Answer 1

Explanation:

Apologies there was a mistake in my last answer. This should be right now if not correct me.

The formula for calculating the boiling point at a given elevation is:

b = 212 - (1.72 * (h / 1000))

To solve for the elevation when the boiling point is 190°F, we can rearrange the formula:

190 = 212 - (1.72 * (h / 1000))

First, subtract 212 from both sides:

190 - 212 = -1.72 * (h / 1000)

Then, divide both sides by -1.72:

-22 / -1.72 = h / 1000

Simplifying the left side:

12.79 ≈ h / 1000

Finally, multiply both sides by 1000 to isolate h:

12.79 * 1000 ≈ h

Therefore, the elevation when the boiling point for water is 190°F is approximately 12,790 feet.