Question

A bowling ball m=1.1 kg is dropped from a height h. It falls a distance, d. before encountering a large tube r=3.9 m which is connected by two bolts, Each bolt can individually sustain a force of F=130 N before failing. Q2 50% Part (a) Write an expression for the maximum distance, d, above the pipe from which the ball can be dropped so the bolts do sot fail. d=(Fr)(mg)× Artempla Kreinith Ferbbeck: in mailuble.

Answer 1

The maximum distance above the pipe from which the ball can be dropped without the bolts failing is 15.05 meters

Step-by-step explanation:

To determine the maximum distance, d, above the pipe from which the ball can be dropped without the bolts failing, we can use the equation d = (Fr) / (mg). In this equation, F is the force each bolt can sustain before failing, r is the radius of the pipe, m is the mass of the bowling ball, and g is the acceleration due to gravity.

Plugging in the given values, we have d = (130 N)(3.9 m) / (1.1 kg)(9.8 m/s²) = 15.05 m. Therefore, the maximum distance above the pipe from which the ball can be dropped without the bolts failing is 15.05 meters.