Sure, let's proceed step by step to calculate this.
The first key point here is that we have a square current loop in a magnetic field. This means we can compute the magnetic moment of the loop then find the torque on the loop.
Step 1: Convert the Side Length to Meters
For easier calculations and standard unit convention, it's best to convert cm to meters. The side length of the square loop is 9.75 cm. To convert this to meters, we divide by 100, so the side length in meters is 9.75/100 = 0.0975 m.
Step 2: Calculate the Magnetic Moment
The magnetic moment (mu) of a current loop is given by the product of the current, I, and the area of the loop, A. For a square loop, the area is side length^2. So, here we find that the area of our loop is (0.0975 m)^2 = 0.00950625 m^2. Thus, the magnetic moment is mu = I*A = 1.73 A * 0.00950625 m^2 = 0.0164458125 A.m^2.
Step 3: Calculate the Torque
The torque (N) on a current loop in a magnetic field B is given by N = mu * B. Here, mu is the magnetic moment we calculated in Step 2, and B is the provided magnetic field, which is 0.283 T. Inserting our calculated mu and the provided B into this formula gives N = 0.0164458125 A.m^2 * 0.283 T = 0.0046541649375 N.m.
So, in conclusion:
- The magnetic moment of the current loop is 0.0164458125 A.m^2.
- The torque on the current loop in the uniform magnetic field is 0.0046541649375 N.m.