Question

A bowling competition had teams competing for the highest number of strikes during a single bowling game. In reviewing the results of a random sample of teams for this bowling competition, the score keeper found the mean number of strikes was x¯=19, with a margin of error of 3. Construct a confidence interval for the mean number of strikes.

Answer 1

To construct a confidence interval for the mean number of strikes in the bowling competition, use the formula (x¯ - margin of error, x¯ + margin of error). For the given values, the confidence interval is (16, 22), indicating that the true mean number of strikes is between 16 and 22 with 90% confidence.

Step-by-step explanation:

To construct a confidence interval for the mean number of strikes in the bowling competition, we can use the formula: (x¯ - margin of error, x¯ + margin of error). Given that x¯ = 19 and the margin of error = 3, the confidence interval is (19 - 3, 19 + 3), which simplifies to (16, 22). Therefore, we can be 90% confident that the true mean number of strikes in the bowling competition is between 16 and 22.

Answer 2

83/3

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