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A distribution of values is normal with a mean of 87.6 and a standard deviation of 39.3. Find P99, which is the score separating the bottom 99% from the top 1%.
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A distribution of values is normal with a mean of 87.6 and a standard deviation of 39.3. Find P99, which is the score separating the bottom 99% from the top 1%.

User Yevgen
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data 99%×39.3÷99+1

after getting it you will be able to get it done

User Theringostarrs
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Heeeeeelp Find the z score that corresponds to P99, the 99th percentile of a standard normal distribution curve.
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