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Find the length of BC and BE (show work please)

Find the length of BC and BE (show work please)-example-1

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Answer:

BC = 4 cm

BE = 10.39

Explanation:

ABCD is an isosceles trapezoid.

Measures of base angles of an isosceles trapezoid are equal.


\therefore m\angle ABC = m\angle DCB


\because m\angle DCB = 120\degree


\therefore m\angle ABC = 120\degree


m\angle ABE = 120\degree-90\degree


m\angle ABE = 30\degree

in triangle ABE,


\cos 30\degree =(BE)/(12)


(\sqrt 3)/(2) =(BE)/(12)


BE = (\sqrt 3* 12)/(2)


BE =6\sqrt 3\: cm


BE = 10.39 cm


\sin 30\degree =(AE)/(12)


(1)/(2) =(AE)/(12)


AE = (12)/(2)


AE =6 \: cm

Next, Draw
CF\perp AD

FD = AE = 6

EF = 16 - (AE + FD) = 16 - (6+6) = 16-12

EF = 4 cm

BCFE is a rectangle.

Measures of the opposite sides of a rectangle are equal.

Therefore

BC = EF

BC = 4 cm

User Rootatdarkstar
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