Answer:
The probability that Zuri draws a red ball is 2/5.
Given that Zuri draws a red ball, the probability that the discarded balls were both green is 66/171.
Explanation:
To find the probability that Zuri draws a red ball, we need to consider the total number of balls and the number of red balls in the box.
The total number of balls in the box is 8 (red) + 12 (green) = 20.
The probability of drawing a red ball is the number of red balls divided by the total number of balls: 8/20 = 2/5.
Now let's move on to the second part of the question. Given that Zuri draws a red ball, we want to find the probability that the discarded balls were both green.
When Zuri draws a red ball, there are 7 red balls and 12 green balls left in the box. The total number of balls remaining is 7 (red) + 12 (green) = 19.
To find the probability that both discarded balls were green, we need to consider the number of ways we can choose 2 green balls out of the remaining 12 green balls, divided by the total number of ways we can choose 2 balls from the remaining 19 balls.
The number of ways to choose 2 green balls out of 12 is given by the combination formula: C(12, 2) = 66.
The total number of ways to choose 2 balls out of 19 is given by the combination formula: C(19, 2) = 171.
Therefore, the probability that the discarded balls were both green, given that Zuri draws a red ball, is 66/171.
To summarize:
(i) The probability that Zuri draws a red ball is 2/5.
(ii) Given that Zuri draws a red ball, the probability that the discarded balls were both green is 66/171.
hope it helped <3
⠀⠀⠀⠀⢀⣀⣀⡀⠀⠀⠀⠀⠀⠀⠀⣠⠾⠛⠶⣄⢀⣠⣤⠴⢦⡀⠀⠀⠀⠀
⠀⠀⠀⢠⡿⠉⠉⠉⠛⠶⠶⠖⠒⠒⣾⠋⠀⢀⣀⣙⣯⡁⠀⠀⠀⣿⠀⠀⠀⠀
⠀⠀⠀⢸⡇⠀⠀⠀⠀⠀⠀⠀⠀⢸⡏⠀⠀⢯⣼⠋⠉⠙⢶⠞⠛⠻⣆⠀⠀⠀
⠀⠀⠀⢸⣧⠆⠀⠀⠀⠀⠀⠀⠀⠀⠻⣦⣤⡤⢿⡀⠀⢀⣼⣷⠀⠀⣽⠀⠀⠀
⠀⠀⠀⣼⠃⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠉⠙⢏⡉⠁⣠⡾⣇⠀⠀⠀
⠀⠀⢰⡏⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠙⠋⠉⠀⢻⡀⠀⠀
⣀⣠⣼⣧⣤⠀⠀⠀⣀⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣀⡀⠀⠀⠐⠖⢻⡟⠓⠒
⠀⠀⠈⣷⣀⡀⠀⠘⠿⠇⠀⠀⠀⢀⣀⣀⠀⠀⠀⠀⠿⠟⠀⠀⠀⠲⣾⠦⢤⠀
⠀⠀⠋⠙⣧⣀⡀⠀⠀⠀⠀⠀⠀⠘⠦⠼⠃⠀⠀⠀⠀⠀⠀⠀⢤⣼⣏⠀⠀⠀
⠀⠀⢀⠴⠚⠻⢧⣄⣀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣀⣤⠞⠉⠉⠓⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠈⠉⠛⠛⠶⠶⠶⣶⣤⣴⡶⠶⠶⠟⠛⠉⠀⠀⠀⠀⠀⠀⠀