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A beaker contains 1.5 x 1023 zinc atoms. How many moles of zinc are present in the beaker?

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Answer:


\huge{ \boxed{0.249 \: \text{moles}}}

Step-by-step explanation:

The number of moles of zinc atoms can be found by using the formula;


n = (N)/(L)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question N = 1.5 × 10²³ zinc atoms.


\therefore \: n = \frac{1.5 * {10}^(23) }{6.02 * {10}^(23) } \\ = 0.249 \: \text{moles}

User Kuldeep Kapade
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