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A force of 200 N is exerted on an object of mass 40 kg that is located on a sheet of perfectly smooth ice. 200N/40kg F 2 A. B. If a second object identical to the first object is placed on top of the first object, what acceleration would the 200 N force produce?​

User Viktar K
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Answer:

If a force of 200 N is exerted on an object of mass 40 kg, we can calculate the acceleration of the object using Newton's second law of motion:

F = m * a

where:

F is the force applied (200 N),

m is the mass of the object (40 kg),

a is the acceleration of the object.

Plugging in the values:

200 N = 40 kg * a

Solving for a:

a = 200 N / 40 kg

a = 5 m/s^2

Therefore, the acceleration produced by the 200 N force on the first object is 5 m/s^2.

Now, if a second object, identical to the first object, is placed on top of the first object, the force of 200 N will act on the combined mass of both objects. Since the second object has the same mass (40 kg), the total mass will be 40 kg + 40 kg = 80 kg.

Using the same formula, the acceleration produced by the 200 N force on the combined mass of both objects will be:

a = 200 N / 80 kg

a = 2.5 m/s^2

Therefore, the acceleration produced by the 200 N force on the combined mass of the two objects is 2.5 m/s^2.

User Antti Kuosmanen
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