Question

Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?

Answer 1

`f(x)* g(y)=y^2tan(x)+8tan(x)-(2y^2)/(x)-(16)/(x)`

Explanation:

We are given that

`f(x)=tan(x)-(2)/(x)`

`g(x)=x^2+8`

We have to find
`f(x)* g(y)`

To find the value of
`f(x)* g(y)` we will multiply f(x) by g(y)

`g(y)=y^2+8`

Now,

`f(x)* g(y)=(tanx-(2)/(x))(y^2+8)`

`f(x)* g(y)=tan(x)(y^2+8)-(2)/(x)(y^2+8)`

`f(x)* g(y)=y^2tan(x)+8tan(x)-(2y^2)/(x)-(16)/(x)`

Hence,

`f(x)* g(y)=y^2tan(x)+8tan(x)-(2y^2)/(x)-(16)/(x)`