Question

An elevator accelerates downward at 2.4 m/s² . What force does the elevator’s floor exert on a 52-kg passenger?

Answer 1

The floor of the elevator exerts a force of 124.8 N on the 52-kg passenger when the elevator accelerates downward at 2.4 m/s².

Step-by-step explanation:

When the elevator accelerates downward at 2.4 m/s², the force that the elevator's floor exerts on the 52-kg passenger can be calculated using Newton's second law of motion. The formula is given by F = m*a, where F is the force, m is the mass, and a is the acceleration. Plugging in the values, we get:

F = (52 kg) * (2.4 m/s²) = 124.8 N

Therefore, the floor of the elevator exerts a force of 124.8 N on the passenger.

Answer 2

The force exerted by the elevator's floor on the 52-kg passenger, when the elevator accelerates downward at 2.4 m/s², is -124.8 N.

Step-by-step explanation:

When the elevator accelerates downward at a rate of 2.4 m/s², the force exerted by the elevator's floor on the 52-kg passenger can be calculated using Newton's second law, which states that force equals mass multiplied by acceleration. In this case, the mass is 52 kg and the acceleration is -2.4 m/s² (negative because it's downward). Therefore, the force exerted by the elevator's floor is:

Force = mass × acceleration

Force = 52 kg × (-2.4 m/s²)

Force = -124.8 N

So, the floor of the elevator exerts a downward force of 124.8 Newtons on the passenger.