Question

Write the equation of the line perpendicular to y=5/2x+2 that passes through the point (-3,5)

Answer 1

y = -2/5x + 19/5

Explanation:

a line perpendicular is the "opposite reciprocal" of the slope:

the slope of the equation is 5/2

so the slope of the perpendicular line is -2/5

that means that the new equation is y = -2/5x + b

then plug in your point

5 = 6/5 + b

19/5 = b

y = -2/5x + 19/5