Question

Given f(x)=x^3-8, find the equation of the secant line passing through (-3,f(-3)) and (3,f(3))

Answer 1

y - 19 = 9(x-3)

Explanation:

the secant line is give as f(a) - f(b) / a - b

f(-3) = -35

f(3) = 19

(-35 - 19) / (-3 - 3)

-54 / -6

9

the slope is then defined as 9

then using point slope formula y - y1 = m(x - x1)

y - 19 = 9(x-3)