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4. (8 pts) Calculate the percent yield when 2.98 g of CO2 is produced during the combustion of 2.54 g of acetone,

C3H6O, and unlimited oxygen. MMC3HGO=58.078 g/mol, MMo2 = 32.00 g/mol, MMCo2 = 44.01 g/mol, and
MMH2018.015 g/mol
4
C3H60+4 02 3 CO2 + 3 H₂O

User Lost Robot
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To calculate the percent yield, we need to compare the actual yield (the amount of CO2 produced) to the theoretical yield (the maximum amount of CO2 that could be produced based on the limiting reactant). Here's the step-by-step process:

1) Calculate the moles of acetone (C3H6O):

- Moles of C3H6O = mass / molar mass

- Moles of C3H6O = 2.54 g / 58.078 g/mol = 0.0437 mol

2) Use the balanced equation to determine the stoichiometry between acetone and CO2:

- From the equation: 4 C3H6O + 4 O2 → 12 CO2

- The ratio of moles between acetone and CO2 is 4:12, or 1:3.

3) Calculate the theoretical yield of CO2:

- Theoretical yield of CO2 = moles of acetone * (moles of CO2 / moles of acetone ratio)

- Theoretical yield of CO2 = 0.0437 mol * (3 mol CO2 / 1 mol acetone) = 0.131 mol

4) Calculate the actual yield of CO2:

- Actual yield of CO2 = 2.98 g / 44.01 g/mol = 0.0676 mol

5) Calculate the percent yield:

- Percent yield = (actual yield / theoretical yield) * 100%

- Percent yield = (0.0676 mol / 0.131 mol) * 100% = 51.6%

Therefore, the percent yield of CO2 in this combustion reaction is 51.6%.

User NrNazifi
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