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What is the equation of the lime that is perpendicular to y=1/3x+12 that contains the point (-6,-1)

User Chalitha Geekiyanage
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1 Answer

11 votes
11 votes

In order to find the equation of the perpendicular line. Take into account that the realtion between the slopes of two perpendicular lines is given by:


m_1=-(1)/(m_2)

where m1 and m2 are the slopes of the lines.

The general form of the equation of a line is:

y = mx + b

where m is the slope and b the y-intercept. By comparing the previous equation with the given equation y = 1/3x + 12, you can notice that m=1/3.

If you take this slope as m2, then the slope of the perpendicular line is:


m_1=-(1)/((1)/(3))=-3

Next, consider that the equation of a line can be also written as follow:

y - yo = m(x - xo)

where (xo,yo) is a point of the line. In this case the point is (-6,-1).

Replace the values of xo, yo and m=m2, into the previous equation and solve for y:

y - (-1) = (-3)(x - (-6))

y + 1 = -3x - 18

y = -3x -19

Hence, the equation of the perpendicular line is y = -3x - 19

User Bahri Noredine
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