Final answer:
The harmonic mean of the sample sizes required to achieve a power of 0.80 is 17.39.
Explanation:
The coach wants to calculate the power of his experiment before beginning it. The power of a study measures its ability to detect an effect if there is one. The coach plans to use Cohen's convention for large effect size (d 0.80) and an independent samples t-test to test the hypotheses. To calculate the power of the test, we first need to calculate delta (δ), which is the effect size we want to detect. Since the coach plans to use a large effect size (d 0.80), δ is also 0.80.
To calculate the delta, we need to calculate the pooled standard deviation (sp). We can use the following formula to find sp:
sp = sqrt(((n₁ - 1)s₁² + (n₂ - 1)s₂²) / (n₁ + n₂ - 2))
where n₁ and n₂ are the sample sizes, and s₁ and s₂ are the standard deviations of the two groups. Since we don't have any data yet, we can't calculate sp directly. However, we can estimate it using Cohen's convention for a large effect size, where we assume that the population standard deviations are equal. In this case, we can use the following formula to estimate sp:
sp = sqrt(((n₁ - 1) + (n₂ - 1)) / (n₁ + n₂ - 2)) * d
where d is the effect size, which is 0.80 in this case. Plugging in the values, we get:
sp = sqrt(((16 - 1) + (20 - 1)) / (16 + 20 - 2)) * 0.80
sp = 0.565
Next, we need to calculate the t-value for the desired significance level (α) and sample sizes (n₁ and n₂). In this case, the coach plans to use a significance level of .05, so α = 0.05, and the degrees of freedom (df) = (n₁ + n₂ - 2) = 34. Using a t-table with 34 degrees of freedom and a two-tailed test, we find the t-value to be 1.691.
Finally, we can calculate the power of the test using the following formula:
power = 1 -