147k views
16 votes
find the equation of a line that is parallel to the straight line 2x-y=-3 and crosses the x-axis at x=-5​

User Calteran
by
8.1k points

1 Answer

8 votes

Answer:

y=2x+10

Explanation:

In line equations its helpful to write your line in the form y = ax + b. This helps because a is always the gadient of the line and b is always the y intercept.

In this case it is y=2x+3

All parallel lines have the same gradient. The gradient of this line = 2.

If the line crosses the x axis at x=-5, then when x =-5 y = 0.

If you put all this in the form y =ax + b you get 0 = 2(-5) +b

So all you need to do to find b is rearrange. b = 10.

Therefore your line has gradient 2 and y intercept 10.

y = 2x + 10

User Tobias Brandt
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories