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2 votes
1

2
3
H
1.008
3
Li
6.94
11
Na
22.99
10
OB.
2
4
Be
9.01
O A. 1.27 x 1024
1.81 x 1024
3.80 x 1024
6.28 x 1024
O C.
12
Mg
24.31
30
Select the correct answer.
How many atoms of oxygen are contained in 160 grams of N₂O₂?
D.
3 4
31
5 6
32
21
7 8
35
36
9
37
10
30
11
20
12

User Hadar
by
7.8k points

1 Answer

2 votes

Final answer:

To find the number of atoms of oxygen in 160 grams of N₂O₂, calculate the number of moles of N₂O₂ and then multiply it by Avogadro's number. The number of atoms of oxygen is approximately 2.094 × 10^24 atoms.


Step-by-step explanation:

To find the number of atoms of oxygen in 160 grams of N₂O₂, we need to calculate the number of moles of N₂O₂ and then multiply it by Avogadro's number.

First, we calculate the molar mass of N₂O₂: 2(14.01) + 2(16.00) = 92.02 g/mol.

Next, we can calculate the number of moles of N₂O₂ by dividing the mass given (160 grams) by the molar mass (92.02 g/mol): 160 g / 92.02 g/mol = 1.739 mol.

Since there are two oxygen atoms in each molecule of N₂O₂, we multiply the number of moles by 2 to get the number of oxygen atoms: 1.739 mol × 2 = 3.479 mol. To convert this to atoms, we multiply by Avogadro's number (6.022 × 10^23 atoms/mol) to get 3.479 mol × 6.022 × 10^23 atoms/mol ≈ 2.094 × 10^24 atoms of oxygen.


Learn more about atoms of oxygen

User Terry Brown
by
7.6k points