Question

HELLPP PLEASEEEEE I NEED TO PASS THIS

Answer 1

to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture below.

`(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{-10}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-10}-\stackrel{y1}{(-2)}}}{\underset{\textit{\large run}} {\underset{x_2}{5}-\underset{x_1}{(-3)}}} \implies \cfrac{-10 +2}{5 +3} \implies \cfrac{ -8 }{ 8 } \implies -1`

`\begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-2)}=\stackrel{m}{-1}(x-\stackrel{x_1}{(-3)}) \implies y +2 = -1 ( x +3) \\\\\\ y+2=-x-3\implies {\Large \begin{array}{llll} y=-x-5 \end{array}}`