Question

What is the index of refraction of a substance if the critical angle for a ray going into Water (n=1.33) is 69.30?1.422.2652.11.24

Answer 1

First, remembering Snell's law, we know that:

`sin(\theta)=(n_(entering))/(n_(leaving))`

So, we know that n_entering is 1.33, as the ray is entering water, and we have the angle, thus:

`sin(69.30°)=(1.33)/(n_(leaving))`

And therefore:

`n_(leaving)=(1.33)/(sin(69.30°))=1.42`