Question

Based on data from a college, scores on a certain test are normally distributed with a mean of 1517 and a standard deviation of 328. Find the percentage of scores greater than 1845.

Answer 1

Hi,

Explanation:

`Z=(X-\mu)/(\sigma) =(1845-1517)/(328) =1\\\\p(X > 1845)=1-p(X\leq 1845)=1-p(Z\leq 1)=1-0.8413=\boxed{0,1587=18.87\%}`