Question

Over the past 6 seasons, one baseball player's batting averages were 0.248, 0.302, 0.248, 0.307, 0.295, and 0.369. A second player's batting averages were 0.349, 0.231, 0.272,0.263, 0.275, and 0.384. What are the range and mean of each player's batting averages? Use your results to compare the players' batting skills.Find the range and mean of the first player's batting averages.The range is (Type an integer or a decimal.)(Round to the nearest thousandth as needed.)The mean is

Answer 1

First let's write down the batting averages of the first player in ascending order:-

0.248, 0.248, 0.295, 0.302, 0,307, 0,369

The difference between the largest value and the minimum value will give us the range:-

So range for the first player will be = 0.369 - 0.248 = 0.121

Now let;s calculate the mean of the first palyer's batting averages

`\begin{gathered} \text{Mean}_1=(0.248+0.248+0.295+0.302+0.307+0.369)/(6) \\ =(1.769)/(6) \\ =0.295\text{ (approx)} \end{gathered}`

Now let's write down the batting averages of the second player in ascending order

0.231, 0.263, 0.272, 0.275, 0.349, 0.384

So the range for second player will be:-

0.384-0.231= 0.153

Now let;s calculate the mean of the second palyer's batting averages

The mean for second player is 0.296 (approx)

And the mean for the first player is 0.295 (approx)

Since the mean avarage of both the players is almost same but the range of second player is more than that of first player, so the second player has good batting skills as compared to the first player.