Answer:
![(a+b)^(2)- \sqrt[3]{x . 3y}](https://img.qammunity.org/2022/formulas/mathematics/high-school/wsxcan2jpvei37czsautgbd75emj7hp56v.png)
Explanation:
Subtract the cube root of the product of x and 3y from the square of the sum of a and b.
A = The square of the sum of a and b is
![(a+b)^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/u7cfewon8q6vppbympybw82ewkjxkscy7w.png)
B = The cube root of the product of x and 3y is
![\sqrt[3]{x . 3y}](https://img.qammunity.org/2022/formulas/mathematics/high-school/qgzw0bszg35h02p1sjnhvwwvqaha98bfzg.png)
They want us to subtract B from A so B - A, therefore the following.