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Evaluate h(3x) where h(y)=y³ − 4/8y . h(3x)= Evaluate g(x+2) where g(x)=3x² − 6x + 8. g(x+2)=

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Answer: To evaluate h(3x), we need to substitute 3x into the function h(y) = y³ - (4/8)y.

Replacing y with 3x, we have:

h(3x) = (3x)³ - (4/8)(3x)

Simplifying this expression:

h(3x) = 27x³ - (1/2)x

Therefore, h(3x) is equal to 27x³ - (1/2)x.

Moving on to evaluating g(x+2), we substitute x+2 into the function g(x) = 3x² - 6x + 8.

Replacing x with x+2, we have:

g(x+2) = 3(x+2)² - 6(x+2) + 8

Expanding and simplifying this expression:

g(x+2) = 3(x² + 4x + 4) - 6x - 12 + 8

g(x+2) = 3x² + 12x + 12 - 6x - 4

Combining like terms:

g(x+2) = 3x² + 6x + 8

Therefore, g(x+2) is equal to 3x² + 6x + 8.

User Alexander Rolek
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