To find the acceleration of the 3 kg block when a force of 31 N is applied, you can use Newton's second law of motion, which states that:
\[F = ma\]
Where:
- \(F\) is the force applied (31 N in this case)
- \(m\) is the mass of the object (3 kg)
- \(a\) is the acceleration
Rearrange the equation to solve for acceleration:
\[a = \frac{F}{m}\]
Now, plug in the values:
\[a = \frac{31 \, \text{N}}{3 \, \text{kg}}\]
Calculate the acceleration:
\[a = 10.33 \, \text{m/s}^2\]
So, the acceleration of the 3 kg block is approximately \(10.33 \, \text{m/s}^2\).