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Given circle E with diameter CD and radius EA. AB is tangent to E at A. If AC=28 and AD=15, solve for CD. Round your answer to the nearest tenth if necessary. If the answer.cannot be determined, click "Cannot be determined."

User Chydik
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1 Answer

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In this problem, you have a circle E with diameter CD, and radius EA. The line AB is tangent to the circle at point A. We're given AC = 28 and AD = 15, and we need to find CD.

First, let's draw a diagram:

```
C
|\
| \
| \
| \ E
| \
| \
15 | \
| \
| \
|_________\
A B D
```

Now, let's use the information we have:

1. AC = 28
2. AD = 15

Since AC is the diameter of the circle, and AD is a radius, we know that CD (the other radius) is also 28 (twice the length of AD).

Now, we have CD = 28, and we can round it to the nearest tenth if necessary. In this case, there's no rounding needed because 28 is a whole number.

So, CD = 28.
User Denisafonin
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