Question

A1=1 and an+1=(an)^2+3 then find value of a 4

Answer 1

a₄ = 364

Explanation:

using the recursive rule
`a_(n+1)` = (
`a_(n)` )² + 3 , eith a₁ = 1 , then

a₁ = 1

a₂ = (a₁ )² + 3 = 1 + 3 = 4

a₃ = (a₂ )² + 3 = 4² + 3 = 16 + 3 = 19

a₄ = (a₃ )² + 3 = 19² + 3 = 361 + 3 = 364