Answer:
EB= 6 units
Explanation:
From the diagram we have,
Chords AB and CD are equidistant from the centre of the circle
I.e. at a distance of 5 units from the centre each
Thus from your theorem
Equidistant chords of a circle are equal in length we get
Length of AB= length of CD= 12 units
Also by theorem perpendicular from centre of circle to chord bisects it
Thus AE= EB
But AE+EB= 12
=>EB= 6 units....(ans)