Question

sodium and oxygen react to produce sodium oxide how many moles of oxygen are needed to produce 11.15 g of sodium oxide

Answer 1

0.0899 moles of oxygen (O2).

Step-by-step explanation:

What is given?

Mass of sodium oxide (Na2O) = 11.15 g.

Molar mass of Na2O = 62 g/mol.

Step-by-step solution:

First, let's state the balanced chemical equation:

`4Na+O_2\rightarrow2Na_2O.`

Let's calculate the moles of Na2O that are in 11.15 g of Na2O, using its molar mass:

`11.15\text{ g Na}_2O\cdot\frac{1\text{ mol Na}_2O}{62\text{ g Na}_2O}=0.1798\text{ moles Na}_2O.`

Now that we have the moles of Na2O, let's do the stoichiometry: you can see in the chemical equation that 1 mol of oxygen (O2) reacted produces 2 moles of Na2O, so by doing a rule of three based on this data, the calculation will look like this:

`0.1798\text{ moles Na}_2O\cdot\frac{1\text{ mol O}_2}{2\text{ moles Na}_2O}=0.0899\text{ moles O}_2.`

The answer is that we need 0.0899 moles of oxygen (O2) to produce 11.15 g of sodium oxide.