Question

Given that RS = 2x + 8 and ST = 2x - 4,
and RT = 20. Solve for x.

Answer 1

I'm assuming points R, S, and T are on the same straight line.

If so, then we use the segment addition postulate.

RS + ST = RT

(2x+8) + (2x-4) = 20

4x+4 = 20

4x = 20-4

4x = 16

x = 16/4

x = 4 is the final answer