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Calculate the empirical formula of each compound from the percent composition of 5.13 g of Cr and 2.37 g of O

User Draw
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1 Answer

4 votes

Answer:

Cr2O3

Step-by-step explanation:

Moles of Cr=5.13/52=0.09865...

Moles of O=2.37/16=0.148125

Ratio of Cr to O=0.09865/0.148125=0.666

which is about 2/3.

Thus empirical formula is Cr2O3

User Jenko
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