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What pressure is exerted by 969.6 g of CH4 in a 0.680 L steel container at 279.8 K?
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What pressure is exerted by 969.6 g of CH4 in a 0.680 L steel container at 279.8 K?

User Jgorostegui
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P= nRT/V

V = volume

n = number of gas particles

R = universal gas constant (8.31446261815324 m³⋅Pa⋅K⁻¹⋅mol⁻¹)

T = temperature

P= (60.6x 8.31x 279.8)/0.680
P= 207210.82atm
What pressure is exerted by 969.6 g of CH4 in a 0.680 L steel container at 279.8 K-example-1
User Metin
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