Answer:
A full house has three cards of one kind and two of another, so think about it like this: first you choose a type of card (13 choices), then you choose three out of four of those cards, then you choose a second type of card, and finally you choose two of those four cards. Thus you have (131)(43)(121)(42)
possible full house hands. So the probability is then
(131)(43)(121)(42)(525)=(13)(4)(12)(6)2598960=37442598960≈0.00144
Explanation: