Answer: 4.12 kJ
Step-by-step explanation:
The specific heat capacity of water is 4.184 J/g*C, which means that it takes 4.184 joules to raise the temperature of 1 gram of water 1 degree Kelvin.
The specific heat equation is q = mcΔT, where q is the energy required raise the temperature the desired amount, m is the mass of the sample you are heating or cooling, in this case 56.00 g, c is the specific heat of the sample, in this case 4.184 J/g*C for water, and ΔT is the final temperature minus the initial temperature: 43.9 - 26.3 = 17.6° C.
So, q = 56.00*4.184*17.6 = 4120 J = 4.12 kJ