Question

Liquid hexane (CH3(CH2)CH3) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O).Suppose 28. g of

hexane is mixed with 134. g of oxygen. Calculate the minimum mass of hexane that could be left over by the chemical reaction. Round your answer to 2 significant digits.

Answer 1

Step-by-step explanation:

Sure! To calculate the minimum mass of hexane that could be left over, we need to determine which reactant is the limiting reagent. This can be done by comparing the moles of each reactant to the stoichiometric ratio in the balanced equation. Once we identify the limiting reagent, we can calculate the mass of hexane remaining.

First, we need to convert the given masses of hexane and oxygen to moles using their respective molar masses. Then, we compare the moles of hexane and oxygen using the stoichiometric coefficients from the balanced equation.

The balanced equation for the reaction is:

C6H14 + 19O2 → 12CO2 + 14H2O

Now, let's calculate the moles of hexane and oxygen:

Moles of hexane = mass of hexane (in g) / molar mass of hexane

Moles of oxygen = mass of oxygen (in g) / molar mass of oxygen

Next, we need to compare the moles of hexane and oxygen by dividing the moles of each reactant by their respective stoichiometric coefficients in the balanced equation.

Finally, we calculate the minimum mass of hexane that could be left over by multiplying the moles of hexane by the molar mass of hexane.

Let's calculate it step by step!