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If it takes 481 J of energy to warm 7.40 g of water by 19°C, how much heat would be needed to warm 7.40 g of water by 49°C

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To calculate the amount of heat needed to warm 7.40 g of water by 49°C, you can use the formula for heat energy:

Q = mcΔT

Where:

Q is the heat energy in joules (J)
m is the mass of the substance in grams (g)
c is the specific heat capacity of the substance (water has a specific heat capacity of approximately 4.18 J/g°C)
ΔT is the change in temperature in degrees Celsius (°C)
You have already been given the mass (m) and the change in temperature (ΔT), and you know the specific heat capacity (c) of water.

m = 7.40 g
ΔT = 49°C
c (specific heat capacity of water) = 4.18 J/g°C

Now, plug these values into the formula:

Q = (7.40 g) * (4.18 J/g°C) * (49°C)

Calculate this to find the heat energy required:

Q = 1543.394 J (rounded to three decimal places)

So, you would need approximately 1543.394 joules of heat energy to warm 7.40 g of water by 49°C.
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