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In ΔMNO, the measure of ∠O=90°, the measure of ∠N=70°, and OM = 3.3 feet. Find the length of MN to the nearest tenth of a foot.

User Lancew
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1 Answer

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Answer:

Side MN = 3.5

Explanation:

Side NO = 1.2011

Side OM = 3.3

Side MN = 3.51179

Angle ∠M = 20° = 0.34907 rad = π/9

Angle ∠N = 70° = 1.22173 rad = 7/18π

Angle ∠O = 90° = 1.5708 rad = π/2

In ΔMNO, the measure of ∠O=90°, the measure of ∠N=70°, and OM = 3.3 feet. Find the-example-1
User Aron Asztalos
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