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What would be the 'a' value in y = x2 + 8x +15?

User Gaz Smith
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2 Answers

2 votes

Answer: a=1

Explanation:

In the equation y = x^2 + 8x + 15, the 'a' value refers to the coefficient in front of the x^2 term. In this case, the 'a' value is 1 because there is no number explicitly written in front of the x^2 term. To understand this better, let's break down the equation: y = x^2 + 8x + 15 The x^2 term represents the squared value of x. The coefficient in front of this term, which is 'a', determines the shape and direction of the parabola. In this equation, since there is no number explicitly written in front of the x^2 term, we assume the coefficient to be 1. This means that the parabola opens upwards and is relatively wider compared to parabolas with larger 'a' values. It's important to note that the value of 'a' affects the overall shape of the parabola. For example, if the value of 'a' were negative, the parabola would open downwards. So, in the equation y = x^2 + 8x + 15, the 'a' value is 1.


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User Ryno
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6.9k points
7 votes

Answer:

a = 1

Explanation:

y = x² + 8x + 15

The leading term in a polynomial is the term with the highest degree.

The leading coefficient in a polynomial is the coefficient of the leading term.

1

User EkcenierK
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7.0k points