Question

Suppose that x and y are real numbers, and x^2 + y^2 = 4. Find all ordered pairs (x, y) that satisfy this equation. A) (2, 0) B) (0, 2) C) (-2, 0) D) (0, -2)

Answer 1

All of them satisfy the equation.

Explanation:

x^2 + y^2 = 4

2^2 + 0^2 = 4 True

0^2 + -2^2 = 4 True

-2^2 + 0^2 = 4 True

0^2 + -2^2 = 4 True