161k views
1 vote
Suppose that x and y are real numbers, and x^2 + y^2 = 4. Find all ordered pairs (x, y) that satisfy this equation. A) (2, 0) B) (0, 2) C) (-2, 0) D) (0, -2)

1 Answer

5 votes

Answer:

All of them satisfy the equation.

Explanation:

x^2 + y^2 = 4

2^2 + 0^2 = 4 True

0^2 + -2^2 = 4 True

-2^2 + 0^2 = 4 True

0^2 + -2^2 = 4 True

User Simon Ludwig
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories