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The primary means by which a neuron can communicate to a second neuron is by A) the frequency of its action potentials. B) the peak of the depolarization phase of an action potential. C) the peak of the undershoot/hyperpolarization of an action potential. D) varying how much neurotransmitter it releases for a given action potential. E) remaining in the depolarization phase of the action potential for an extended interval.

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Final answer:

The primary means by which a neuron can communicate to a second neuron is by varying how much neurotransmitter it releases for a given action potential.

Step-by-step explanation:

The primary means by which a neuron can communicate to a second neuron is by varying how much neurotransmitter it releases for a given action potential. When an action potential reaches the end of an axon, neurotransmitter molecules are released into the synaptic cleft between the synaptic knob of the axon and the post-synaptic membrane of the next cell. The neurotransmitter diffuses across the synaptic cleft and binds to receptors in the post-synaptic membrane, which can cause excitatory or inhibitory postsynaptic potentials.

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