Question

An arrow is launched upward with a velocity of 288 feet per second from the top of a 55-foot structure. What is the maximum height attained by the arrow?

Answer 1

1343 ft

Step-by-step explanation:

vf^2 = vi^2 +2ad
given the initial ( launched) speed equal to 288ft/s and a which is -9.81 m/s^2 or -32.2 ft/s^2 ( use same unit as velocity )
0^2 = 288^2 + 2(-32.2) d
d= 1288ft
since the initial distance is 55 ft , the total distance from ground to the arrow distance = 55 ft + 1288 ft =1343 ft